How many kgs of salt at 42p per kg must a man mix with 25 kgs of salt at 24p per kg so that he may, by selling the mixture at 40p per kg, gain 25 $%$ on the outlay?

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Solution

The correct option is A
20

$Cost price of mixture = 40 \times \frac{100}{125} = 32 p per kg$

$Ratio = 4:5 Thus for every 5 kg of salt at 24p, 4 kg of salt at 42p is used. ∴ The required kgs of salt at 42p per kg = 25 \times \frac{4}{5} = 20$

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How many kgs of salt at 42p per kg must a man mix with 25 kgs of salt at 24p per kg so that he may, by selling the mixture at 40p per kg, gain 25% on the outlay?

The correct option is A 20 Cost price of mixture =40×100125 = 32p per kg Ratio = 4:5Thus for every 5 kg of salt at 24p, 4 kg of salt at 42p is used.∴The required kgs of salt at 42p per kg=25×45 = 20

How many kgs of salt at 42p per kg must a man mix with 25 kgs of salt at 24p per kg so that he may, by selling the mixture at 40p per kg, gain 25 $%$ on the outlay?

The correct option is A
20

$Cost price of mixture = 40 \times \frac{100}{125} = 32 p per kg$

$Ratio = 4:5 Thus for every 5 kg of salt at 24p, 4 kg of salt at 42p is used. ∴ The required kgs of salt at 42p per kg = 25 \times \frac{4}{5} = 20$